An ideal gas occupies a volume of 0.50 liter at a pressure of 0.20 atmosphere. What volume will the gas occupy at 0.40 atmosphere if the temperature remains constant?

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Multiple Choice

An ideal gas occupies a volume of 0.50 liter at a pressure of 0.20 atmosphere. What volume will the gas occupy at 0.40 atmosphere if the temperature remains constant?

Explanation:
For a gas at constant temperature, pressure and volume are inversely related (Boyle’s law): P1V1 = P2V2. Here, P1 = 0.20 atm and V1 = 0.50 L, P2 = 0.40 atm. Solve for V2: V2 = (P1V1) / P2 = (0.20 × 0.50) / 0.40 = 0.10 / 0.40 = 0.25 L. Doubling the pressure halves the volume, so the gas occupies 0.25 liters.

For a gas at constant temperature, pressure and volume are inversely related (Boyle’s law): P1V1 = P2V2.

Here, P1 = 0.20 atm and V1 = 0.50 L, P2 = 0.40 atm. Solve for V2:

V2 = (P1V1) / P2 = (0.20 × 0.50) / 0.40 = 0.10 / 0.40 = 0.25 L.

Doubling the pressure halves the volume, so the gas occupies 0.25 liters.

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