The perimeter of a rectangle is 240 inches. If the length is twice the width, what are the dimensions of the rectangle?

Master the NLN PAX Mathematics 1 Exam with our comprehensive study guide and quizzes. Test your knowledge with multiple choice questions tailored for the PAX Math exam, featuring detailed explanations and tips to enhance your preparation and increase your chances of success.

Multiple Choice

The perimeter of a rectangle is 240 inches. If the length is twice the width, what are the dimensions of the rectangle?

Explanation:
The key idea is using the perimeter formula and the given relationship between length and width. The perimeter of a rectangle is 2 times the sum of its length and width, so 2(L + W) = 240, which gives L + W = 120. Since the length is twice the width, let L = 2W. Substitute: 2W + W = 120, so 3W = 120 and W = 40. Then L = 2W = 80. The dimensions are 40 inches by 80 inches, and verifying: 2(40 + 80) = 240.

The key idea is using the perimeter formula and the given relationship between length and width. The perimeter of a rectangle is 2 times the sum of its length and width, so 2(L + W) = 240, which gives L + W = 120. Since the length is twice the width, let L = 2W. Substitute: 2W + W = 120, so 3W = 120 and W = 40. Then L = 2W = 80. The dimensions are 40 inches by 80 inches, and verifying: 2(40 + 80) = 240.

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